Pentru suma numerelor consecutive folosesti formula lui Gauss: n(n+1)/2
[tex] \sqrt{ \frac{1+2+3+...+50}{1+2+3+...+51} } = \sqrt{ \frac{50(50+1)/2}{51(51+1)/2} } =[/tex]
[tex]\sqrt{ \frac{25*52}{51*26} } = \sqrt{ \frac{ 5^{2}* 2^{2}*13 }{51*2*13} } = \sqrt{ \frac{ 5^{2}*2 }{51} } =5 \sqrt{ \frac{2}{51} } [/tex]
