√2+√3+√200-√300+2√50-2√75 .
Va rog vreau rezolvarea... Nu pot sa il fac, ma blochez undeva

√2+√3+10√2-10√3+10√2-10√3=21√2-19√3

[tex]\displaystyle \sqrt{2} + \sqrt{3} + \sqrt{200} - \sqrt{300} +2 \sqrt{50} -2 \sqrt{75}= \\ \\ = \sqrt{2} + \sqrt{3} +10 \sqrt{2} -10 \sqrt{3} +2 \cdot 5 \sqrt{2} -2 \cdot 5 \sqrt{3} = \\ \\ = \sqrt{2} + \sqrt{3} +10 \sqrt{2} -10 \sqrt{3} +10 \sqrt{2} -10 \sqrt{3} =21 \sqrt{2} -19 \sqrt{3} [/tex]