limita cand x tinde la 0 din (sin patrat din 2x)/5x patrat

Răspuns :

[tex]\displaystyle \lim_{x \to 0} \frac{sin^2(2x)}{(5x)^2} =\\ =\lim_{x \to 0} ( \frac{sin(2x)}{(5x)})^2 =( \frac{2}{5} )^2= \frac{4}{25} [/tex]