I. md1=(20*300)/100=60g HCl (20%)
md2=(40*600)/100=240g HCl (40%)
md3=60+240=300g
ms3=300+600+100=1000g
c3=(100*300)/1000=30%
II. md1=(5*200)/100=10 => m apa=200-10=190
md2=[c2*(190+md2)]/100=(190*20+20md2)/100
100md2=3800+20md2
80md2=3800
md2=47,5 => m apa adaugata=47,5-10=37,5g sare
Sper ca ai inteles si ca te-am ajutat ;)
coronita? :3