[tex] \pi RG=544 \pi ;RG=544;R= \frac{544}{G} \\ G^2-R^2=H^2 \\ G^2-( \frac{544}{G})^2=900 \\ G^4-900G^2-544=0
\\ fie :G^2=t;t \geq 0 \\ t^2-900t-295936=0 [/tex]
Δ=810000+1183744=1993744
[tex] t_{1}= \frac{900-1412}{2}= -256 \\ t_{2} = \frac{900+1412}{2}=1156 [/tex]
revenim la substitutie
[tex]G^2=1156 \\ G=34cm \\ R= \frac{544}{34}=16cm [/tex]
