Sa se determine baza logaritmilor
Log in baza a din din 2 = 4
Log in baza a din 3=1/3
Log in baza a din radical din 3=1/2
Log in baza a din 1/25=-2


Răspuns :

[tex] log_{a}3= \frac{1}{3},deci,a^ \frac{1}{3}=3,sau,a=3^3=27 [/tex][tex] log_{a}2=4,adica,a^4=2,deci,a= \sqrt[4]{2} [/tex]
[tex] log_{a} \sqrt{3}= \frac{1}{2},echivalent,cu,a^ \frac{1}{2}= \sqrt{3} ,sau,a=3 [/tex]
[tex] log_{a} \frac{1}{25}=-2,deci,a^{-2} = \frac{1}{25},sau,(a^{-2})^{-1}=( \frac{1}{25}) ^{-1}} },sau,a^2=25,deci [/tex],a=5.
a) [tex] a^{4} =2 , a= \sqrt[4]{2} [/tex]

b) [tex] a^{1/3} =3[/tex], 
    [tex] \sqrt[3]{a}=3[/tex], 
a=3³=27
c) a^{1/2}=√3
    √a=√3 ⇒ a=3

d) a^{-2}=1/25 ⇒1/a²=1/25
a²=25 ⇒ a=5