aflati a,b,c direct proportionale cu 4,5,8 stiind ca 2x+3y+5z=630

Răspuns :

Xa/4=Y/5=Z/8=K
X/4=K=>X=4K; Y/5=K=>Y=5K; Z/8=K=>Z=8K
2×4K+3×5K+5×8K=630 =>8K+15K+40K=630 => 63K=630 => K=10 => X=40; Y=50; Z=80