a+b+c+d = 967
a = 2×d+56
b = d-17 =>d = b+17
c = a:2
a |___|___|+56 +(2×17)
b |___|
c |___|+(90:2) = 45
d |___|+17
avem 5 segmente egale +56+34+45+17 = 967
56+34+45+17 = 152
967 - 152 = 815
815 : 5 = 163 ( un segment)
a = 2×163+56+34 = 326+90 = 416
b = 163
c = 163+45 = 208
d = 163+17 = 180
Verificare:
416+163+208+180 = 967
Cele 4 numere sunt:
416; 163; 208; 180 .