tgB=0,75=75/100
tg=cateta opusa/cateta alaturata
AB=24-----CATETA ALATURATA
BC-----IPOTENUZA
AC------CATETA OPUSA
ΔABC
mA=90
tgB=AC/AB
75/100=AC/24⇒AC=(24*75)/100=1800/100=18
ΔABC
mA=90⇒TEOREMA LUI PITAGORA
BC²=AB²+AC²
BC²=24²+18²
BC²=576+324
BC=√900=30
Perimetrul=AC+BC+AB=18+30+24=72
Aria=(CATETA*CATETA)/2
=(24*18)/
=432/2=216