descompuneti in factori:(2x-3)totul la a treia -8x+12

Răspuns :

(2x-3)totul la a treia -8x+12


(2x-3)^3 - 8x + 12


(2x-3)³ - 8x + 12  = (2x-3)³ - 4(2x - 3) = (2x - 3)[(2x-3)² - 2²] =

=(2x-3)(2x-3-2)(2x-3+2) = (2x - 3)(2x - 5)( 2x - 1) =

=
(2x - 1)(2x - 3)( 2x - 5).