a+b+c = 103 bile
b = a+3
c = a : 2 => a = 2×c
a |___|___|
b |___|___|+3
c |___|
avem 5 segmente egale +3 = 103
103 -3 = 100
100 :5 = 20 (un segment egal)
a = 2×20 = 40
b = 2×20 + 3 = 43
c = 20
Verificare:
40+43+20 = 103
40 bile are primul copil
43 bile al 2-lea copil
20 bile al 3-lea copil