compozitia procentuala de masa a elementelor componente k2co3

Răspuns :

M K2CO3 = 39 x 2 + 12 + 16x3 = 78 + 12 + 48 = 138 u.a.m.

138 g ......... 78g K ...... 12g C .......48g O
100 g ........ xg K ...... yg C ........ zg O

=> x = (78 x 100) : 138 = 56,52%
=> y = (12 x 100) : 138 = 8,69%
=> z = (48 x 100) : 138 = 34, 78