2,3g Na ---> nNa=0,1 moli
din reactia CH3COOH + Na ----> CH3COONa + 1/2 H2 observi ca nNa=nCH3COOH (reactioneaza in raport molar 1:1) ---> nCH3COOH=0,1 moli
Vs=0,1L -----> cM=0,1moli/0,1L-----> cM=1M
nH2=1/2nNa---> nH2=0,05 moli---> VH2=0,05moli*22,4L/mol-->VH2=1,12L deci varianta corecta este B