gaseste 3 numere consecutive impare a caror suma e 99

Răspuns :

a |---| Total 99
b |---|+2
c |---|+4
99-(4+2)=99-6=93
93:3=31
a=31
b=33
c=35
a+(a+2)+(a+4)=99 3a+6=99 3a=93 a=93÷3 a=31 31, 33, 35