[tex] \frac{x^2-9}{x^2+5x+6} * \frac{x-5}{x-3} = \frac{(x-3)(x+3)}{x^2+2x+3x+6} * \frac{x-5}{x-3} = \frac{(x-3)(x+3)}{x(x+2)+3(x+2)} * \frac{x-5}{x-3} = \\ \frac{(x-3)(x+3)}{(x+2)(x+3)} * \frac{x-5}{x-3} [/tex]
se observa ca se simplifica x+3 cu x+3 si x-3 cu x-3. dupa simplificare va ramane rezultatul final:
[tex] \frac{x-5}{x+2} [/tex]
