ab : 23 = c rest 11
ab = 23×c+11
c < 4
daca c= 0
ab = 23×0+11
ab = 11
daca c = 1
ab = 23+11=34
daca c = 2
ab = 23×2+11 = 46+11=57
daca c = 3
ab = 23×3+11 = 69+11 = 80
numerele de doua cifre sunt:
11 ; 34 ; 57 ; 80 .
verificare:
11 : 23 = 0 rest 11
34 : 23 = 1 rest 11
57 : 23 = 2 rest 11
80 : 23 = 3 rest 11
