Δ=(2m+1)²-4m(m-3)=4m²+4m+1-4m²+12m=16m+1
Δ=16m+1<0... m<-1/16... nici o radacina rela
Δ=16m+1...m=-1/16... 2 radacini reale confundate x1=x2=(2m+1)/2m=
(-1/8+1)/(-1/8)= (7/8)/(-1/8)=7/(-1)=-7
verifuicare
-x²/16-(-1/8+1)x-1/16-3=0
-x²/16-7x/8-49/16=0
- (x²+14x+49)=0=-(x+7)²⇒ x1=x2=-7 adevarat
Δ=16m+1>0; m>-1/16 doua radacini reale distincte
suma lor este(2m+1)/m iar produsul este (m-3)/m
discutie functie de m, pt m>-1/16, vezi in tabelele in atasamente
