Fie B si b lungimile bazelor
[tex]A=(B+b)\cdot h[/tex]
Fie m lungimea liniei mijlocii
[tex]m=\frac{B+b}{2}[/tex]
[tex]\frac{B+b}{2}=12\sqrt{2}~cm[/tex]
[tex]B+b=24\sqrt{2}~cm[/tex]
[tex]h=3\sqrt{6}~cm[/tex]
[tex]A=24\sqrt{2}\cdot3\sqrt{6}=72\sqrt{12}=144\sqrt{3}~cm^2[/tex]