Cum pun conditiile la inecuatia [tex] \sqrt[]{x^2-3x+2} \geq x+1[/tex] ?

Răspuns :

Ce ai sub radical ≥0 adica
x²-3x+2≥0
x²-3x+2=0
∆=1
x1,2=3±1/2
x1=2
x2=1