n moli C6H5-CO-Cl + CH3-OH ⇒ C6H5-COOCH3 + HCl
2n moli CH3-CO-Cl + CH3-OH ⇒ CH3-COOCH3 + HCl
3n moli CH3-CO-O-CO-CH3 + CH3-OH ⇒ CH3COOCH3 + CH3-COOH
2n + 3n = 370/74 = 5 n = 1mol
m = 1·136 + 5·74 = 506 g
% CH3-COOCH3 = 37000/506 = 73,12%
% C6H5-COOCH3 = 13600/506 = 26,88%