problema nr.2
latura AB=96/3
AB=32
AM=l√3/2=16√3
AM²=AB*AN
AN=16²*3/32=24=AP
ΔANP este un triunghi echilateral AN=AP
m(∡A)=60°
NP=24
problema nr.3
MN = AB / 2 + BC / 2
12 / 2 + 4 / 2 = 6 + 2 = 8 cm
MP = PN = 8 / 2 = 4 cm
AM = AB / 2 = 12 / 2 = 6 cm
AP = AM + MP = 6 + 4 = 10 cm
PB = AB - AP = 12 - 10 = 2 cm