[tex]\displaystyle Avem~\frac{DN}{CD}=k= \frac{AE}{CE} \Rightarrow AN~||~DE~(T.R.~Thales~in~\Delta ANC). \\ \\ Avem~ \frac{AD}{BD}=k= \frac{ME}{BE} \Rightarrow AM~||~DE~(T.R~Thales~in~ \Delta AMB). \\ \\ Din~AN~||~DE~si~AM~||~DE~rezulta~ca~punctele~A,M,N~sunt \\ \\ coliniare.[/tex]
