rezolva
[6×1000-(25-4-40)×5]-(100×7+1000÷25×35)




Răspuns :

[6×10×100-(100-40)×5]-(700+1400)=
(6×10×100-60×5)-2100=
(6000-300)-2100=
5700-2100=3600
[6×1000-(25-4-40)×5]-(100×7+1000:25×35)=3995;  -(-19)=+19
=(6000+19x5)-(700+40x35)=
=(6000+95)-(700+1400)=
=6095-2100=
=3995