[6-3*(5/11)^0]^-2=
[(2/3)^-2-3/4]^-1=
2^-2+3*(2/3)^-2/2+(1/5)^-1=
[1-(1-2)^-1)^-1]^-1+[1+(1+2)^-1)^-1]^-1=


Răspuns :

succes in activitatea scolara
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