A={x|x € IN* si 2x+1<11}
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Răspuns :

2x+1 < 11 <=>
<=> 2x < 11-1 =>
=> 2x < 10 =>
=> x < 10:2 => x < 5
A={,1,2,3,4}
2x+1∠11
2x∠11-1
2x∠10
x∠5
x∈{1,2,3,4}