Scrieti sub forma unei singure puteri cu exponent numar natural :a) 2^5x2^23; b) 7^32:7^6 ;c) (3^7)^21

Răspuns :

a) 2^5x2^23=2^(5+23)=2^28
b) 7^32:7^6=7^(32-6)=7^28
c) (3^7)^21 = 3^7*21=3^147
a) 2⁵ * 2²³ = 2⁵⁺²³ = 2²⁸ ;
b) 7³² : 7⁶ = 7³²⁻⁶ = 7²⁶ ;
c) (3⁷)²¹  = 3⁷ * ²¹ = 3¹⁴⁷;