[3x]=[tex] \frac{x-1}{2} [/tex]
[tex] \frac{x-1}{2} \leq 3x\ \textless \ \frac{x-1}{2} +1~ si ~ \frac{x-1}{2} [/tex]∈Z
Formam sistemul:
(x-1)/2≤3x
3x<(x+1)/2
x-1≤6x <=> -5x-1≤0 <=> -5x≤1 <=>x≥-1/5
6x<x+1 <=> 5x<1 <=>x<1/5
x∈[-1/5,1/5)
Ecuatia nu are solutie.
