Prin arderea a 1,01 g Zn se obtin 1,257 g oxid de zinc. Determina prin calcule formula acestui oxid.

Răspuns :

Zn + x/2 O2 = ZnOx
M Zn = 65 g/mol
M ZnOx = 65+16x g/mol
65 g Zn.......65+16x g ZnOx
1,01 g Zn...........1,257 g ZnOx
65,65 + 16,16x = 81,705
x = 1
=> ZnO - oxid de zinc