4ˣ-10x2ˣ+16=0 ???????????

4ˣ10x2ˣ160 class=

Răspuns :

2^x = t
t^2-10t+16=0
Δ= b^2-4ac
Δ=100-64=36

t1 = (-b + √Δ) / 2a = (10+6)/2 = 8
t2= (-b -√Δ) / 2a = (10-6)/2 = 2

2^x=8
x=3

2^x=2
x=1