e)[tex] \frac{a+8b}{2b} - \frac{ab }{2b} = \frac{a+7ab}{2b} = \frac{a(1+7b)}{2b} [/tex]
f)[tex] \frac{(x-2)(x+2)}{(3-y)(3+y)} * \frac{3+y}{x-2} - \frac{2}{3-y} = \frac{x+2}{3-y} - \frac{2}{3-y} = \frac{x+2-2}{3-y} = \frac{x}{3-y} [/tex]
g)[tex] \frac{a+b}{3a-b} + \frac{1}{a+b} * \frac{(a+b)(a-b)}{3a-b} = \frac{a+b}{3a-b} + \frac{a-b}{3a-b} = \frac{a+b+a-b}{3a-b} = \frac{2a}{3a-b} [/tex]
