20..................md.....x
Ca+H2O-->CaO+H2
40..................56......2
MCa=ACa=40g/mol
MCaO=ACa+AO=40+16=56g/mol
[tex]md = \frac{20 \times 56}{40} = 28g[/tex]
[tex]x = \frac{2 \times 20}{40} = 1[/tex]
Legea conservă maselor=> msf=msi=> msf=20+100=>120g
ma final=120-(28+1)=91 g apă
[tex]cf = \frac{md}{md + maf} \times 100 \\ cf = \frac{28}{28 + 91} \times 100 = 23.52[/tex]
